All India Institute of Medical Sciences (AIIMS) Rishikesh Notification 2017
Company Website : www.aiimsrishikesh.edu.in
Company Name: All India Institute of Medical Sciences
About Company :
AIIMS Rishikesh is one of the SIX Apex healthcare institutes being established by the Ministry of Health & Family Welfare, Government of India under the Pradhan Mantri Swasthya Suraksha Yojna (PMSSY). With the aim of correcting regional imbalances in quality tertiary level healthcare in the country and attaining self sufficiency in graduate and postgraduate medical education and training, the PMSSY planned to set up 6 new AIIMS institutions in under served areas of the country.
These institutions are being established by an Act of Parliament on the lines of the original All India Institute of Medical Sciences,New Delhi which imparts both undergraduate and postgraduate medical education in all its branches and related fields, along with nursing and paramedical training, to bring together in one place educational facilities of the highest order for the training of personnel in all branches of health care activity.
Qualification: B.SC Nursing Degree/MSc.MBBs
Name of the Post :
1. Professor - 35
2. Additional Professor - 29
3. Associate Professor - 48
4. Assistant Professor - 50
5. Tutor/Clinical Instructor - 33
6. Assistant Nursing Superintendent - 28
7. Staff Nurse Grade II - 1126 posts
Number of Posts: 1350 Posts
Salary : INR Rs. Rs. 37400 - 67000/- With 9000/10500/- Grade Pay (Post 1-4), Rs. 15600 - 39100/- With 8000/5400/- Grade Pay (Post 5,6), Rs. 9300 - 34800/- With 4600/- Grade Pay (Post 7).
Location : All Over India
Age Limit : Should not Exceed 58 Years
How To Apply :
All Eligible and Interested candidates may fill the online application through official website www.aiimsrishikesh.edu.in
Apply Mode: Online
Govt Job Updates
Selection Process:
Written Exam
Interview
Last Date: 31st July 2017
Application Fee:
For General/OBC Candidates Application Fee is 3,000/- For All Other Candidates (SC/ST/PWD) Candidates Application Fee is 100/-
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